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-16=3x^2+15x-27
We move all terms to the left:
-16-(3x^2+15x-27)=0
We get rid of parentheses
-3x^2-15x+27-16=0
We add all the numbers together, and all the variables
-3x^2-15x+11=0
a = -3; b = -15; c = +11;
Δ = b2-4ac
Δ = -152-4·(-3)·11
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{357}}{2*-3}=\frac{15-\sqrt{357}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{357}}{2*-3}=\frac{15+\sqrt{357}}{-6} $
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